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(-4)=2F^2+3F-1
We move all terms to the left:
(-4)-(2F^2+3F-1)=0
We add all the numbers together, and all the variables
-(2F^2+3F-1)-4=0
We get rid of parentheses
-2F^2-3F+1-4=0
We add all the numbers together, and all the variables
-2F^2-3F-3=0
a = -2; b = -3; c = -3;
Δ = b2-4ac
Δ = -32-4·(-2)·(-3)
Δ = -15
Delta is less than zero, so there is no solution for the equation
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